15x^2=71x

Solution for 15x^2=71x equation:

15x^2=71x

We move all terms to the left:

15x^2-(71x)=0

a = 15; b = -71; c = 0;
Δ = b2-4ac
Δ = -712-4·15·0
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-71}{2*15}=\frac{0}{30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+71}{2*15}=\frac{142}{30}
=4+11/15
$